e^{i\pi} + 1 = 0

E = mc^2

\nabla \cdot \mathbf{E} = \frac{\rho}{\varepsilon_0}

\int_{-\infty}^{\infty} e^{-x^2}\,dx = \sqrt{\pi}

i\hbar\frac{\partial}{\partial t}|\psi\rangle = \hat{H}|\psi\rangle

\zeta(s) = \sum_{n=1}^{\infty} \frac{1}{n^s}

a^2 + b^2 = c^2

\Delta x \Delta p \geq \frac{\hbar}{2}

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